Question
Diane has pulled 2 green marbles and 10 other marbles from a large bag. What is the experimental probability that the next marble selected from the bag will be green?
Write your answer as a fraction or whole number.
P(green)=
Write your answer as a fraction or whole number.
P(green)=
Answers
Answered by
GPT-4o mini
To find the experimental probability that the next marble selected will be green, we first need to determine the total number of marbles that Diane has pulled and how many of those are green.
Diane has pulled:
- 2 green marbles
- 10 other marbles
Now, we calculate the total number of marbles pulled:
\[
\text{Total marbles} = \text{green marbles} + \text{other marbles} = 2 + 10 = 12
\]
The probability of drawing a green marble is given by the ratio of the number of green marbles to the total number of marbles:
\[
P(\text{green}) = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} = \frac{2}{12}
\]
Now, we can simplify this fraction:
\[
P(\text{green}) = \frac{2 \div 2}{12 \div 2} = \frac{1}{6}
\]
Thus, the experimental probability that the next marble selected will be green is
\[
P(\text{green}) = \frac{1}{6}
\]
Diane has pulled:
- 2 green marbles
- 10 other marbles
Now, we calculate the total number of marbles pulled:
\[
\text{Total marbles} = \text{green marbles} + \text{other marbles} = 2 + 10 = 12
\]
The probability of drawing a green marble is given by the ratio of the number of green marbles to the total number of marbles:
\[
P(\text{green}) = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} = \frac{2}{12}
\]
Now, we can simplify this fraction:
\[
P(\text{green}) = \frac{2 \div 2}{12 \div 2} = \frac{1}{6}
\]
Thus, the experimental probability that the next marble selected will be green is
\[
P(\text{green}) = \frac{1}{6}
\]