Question
Calculate the molar mass of KMnO4.
Responses
128 g/mol
128 g/mol
158 g/mol
158 g/mol
58 g/mol
58 g/mol
188 g/mol
Responses
128 g/mol
128 g/mol
158 g/mol
158 g/mol
58 g/mol
58 g/mol
188 g/mol
Answers
GPT-4o mini
To calculate the molar mass of potassium permanganate (KMnO4), we will sum the molar masses of each component atom in the compound.
- Potassium (K): 39.1 g/mol
- Manganese (Mn): 54.9 g/mol
- Oxygen (O): 16.0 g/mol (There are 4 oxygen atoms)
Now, let's calculate the total molar mass:
\[
\text{Molar mass of KMnO}_4 = \text{Molar mass of K} + \text{Molar mass of Mn} + 4 \times \text{Molar mass of O}
\]
\[
= 39.1 \, \text{g/mol} + 54.9 \, \text{g/mol} + 4 \times 16.0 \, \text{g/mol}
\]
\[
= 39.1 \, \text{g/mol} + 54.9 \, \text{g/mol} + 64.0 \, \text{g/mol}
\]
\[
= 158.0 \, \text{g/mol}
\]
Therefore, the molar mass of KMnO4 is **158 g/mol**.
- Potassium (K): 39.1 g/mol
- Manganese (Mn): 54.9 g/mol
- Oxygen (O): 16.0 g/mol (There are 4 oxygen atoms)
Now, let's calculate the total molar mass:
\[
\text{Molar mass of KMnO}_4 = \text{Molar mass of K} + \text{Molar mass of Mn} + 4 \times \text{Molar mass of O}
\]
\[
= 39.1 \, \text{g/mol} + 54.9 \, \text{g/mol} + 4 \times 16.0 \, \text{g/mol}
\]
\[
= 39.1 \, \text{g/mol} + 54.9 \, \text{g/mol} + 64.0 \, \text{g/mol}
\]
\[
= 158.0 \, \text{g/mol}
\]
Therefore, the molar mass of KMnO4 is **158 g/mol**.