A line passes through the points (-2, 7) and (3, -8).

Part II: Given the slope (calculated in Part I) and the two points, write TWO EQUATIONS in point-slope form of the line.

Equation 1: _____________

Equation 2: _____________

1 answer

To write the equations in point-slope form, we first need to calculate the slope of the line that passes through the points (-2, 7) and (3, -8).

Step 1: Calculate the slope (m)

The formula for the slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

Using the points \((-2, 7)\) and \((3, -8)\):

\[ x_1 = -2, \quad y_1 = 7, \quad x_2 = 3, \quad y_2 = -8 \]

Plugging in the values:

\[ m = \frac{-8 - 7}{3 - (-2)} = \frac{-15}{3 + 2} = \frac{-15}{5} = -3 \]

The slope of the line (m) is -3.

Step 2: Write the equations in point-slope form

The point-slope form of a line is given by:

\[ y - y_1 = m(x - x_1) \]

We can use either point to create the equations.

Using the point (-2, 7):

\[ y - 7 = -3(x - (-2)) \]

This simplifies to:

\[ y - 7 = -3(x + 2) \]

Equation 1:

\[ y - 7 = -3(x + 2) \]

Using the point (3, -8):

\[ y - (-8) = -3(x - 3) \]

This simplifies to:

\[ y + 8 = -3(x - 3) \]

Equation 2:

\[ y + 8 = -3(x - 3) \]

So the two equations in point-slope form are:

Equation 1: \( y - 7 = -3(x + 2) \)

Equation 2: \( y + 8 = -3(x - 3) \)