Question

Fill in the blanks.
How to Find the y-Intercept
Example
Parabola: y = x'-6x + 8
Step 1: Substitute 0 for x. Solve for y.
; Answer
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y = 8
y - intercept:
Step 2: Write the results as an ordered pair (O, y)
#: (0,8)
#y=02-6(0) +8
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1 Answer
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Answer 1

It looks like you're working through how to find the y-intercept of a parabola given in the form of a quadratic equation. Let's fill in the blanks step by step.

**How to Find the y-Intercept**
Example
Parabola: \( y = x^2 - 6x + 8 \)

**Step 1:** Substitute 0 for \( x \). Solve for \( y \).
So we replace \( x \) with 0 in the equation:

\[ y = (0)^2 - 6(0) + 8 \]
\[ y = 0 - 0 + 8 \]
**Answer:**
\( y = 8 \)
y-intercept: 8

**Step 2:** Write the results as an ordered pair (0, y)
#: \( (0, 8) \)
# \( y = 0^2 - 6(0) + 8 \)
= 8

**1 Answer**
**y-intercept is (0, 8)**

So your final answer can be summarized as:
- The y-intercept is at the point (0, 8).