The equation 4x - 5y = 40 is in standard form and tells us the x-intercept and y-intercept easily. What are the x and y intercepts for this equation?

Question

Responses

The line crosses the x-axis at (0, 10) and the y-axis at (-8, 0)
The line crosses the x-axis at (0, 10) and the y-axis at (-8, 0)

The line crosses the x-axis at (10, 0) and the y-axis at (0, -8)
The line crosses the x-axis at (10, 0) and the y-axis at (0, -8)

The line crosses the x-axis at (4, 40) and the y-axis at (-8, 40)
The line crosses the x-axis at (4, 40) and the y-axis at (-8, 40)

The line crosses the x-axis at (-8, 0) and the y-axis at (0, 10)
The line crosses the x-axis at (-8, 0) and the y-axis at (0, 10)

The line crosses the x-axis at (4, 0) and the y-axis at (0, -5)

Answer 1

To find the x-intercept and y-intercept of the equation \( 4x - 5y = 40 \), we can set y to 0 to find the x-intercept, and x to 0 to find the y-intercept.

1. Finding the x-intercept: Set \( y = 0 \): \[ 4x - 5(0) = 40 \implies 4x = 40 \implies x = 10 \] So the x-intercept is \( (10, 0) \).

2. Finding the y-intercept: Set \( x = 0 \): \[ 4(0) - 5y = 40 \implies -5y = 40 \implies y = -8 \] So the y-intercept is \( (0, -8) \).

Thus, the correct answer is: The line crosses the x-axis at (10, 0) and the y-axis at (0, -8).