Question

Consider a particle with initial velocity that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

Answer 1

Is there a question in this?

Answer 2

The questions is x component of the vector?

Answer 3

First set up your cartesian coordinate system. You find that the "magnitude" of the velocity vector is the hypotenuse of your newly formed right triangle. Use trigonometric functions (sin,cos,tan) to find this x-component of the vector.