Asked by tod
Consider a particle with initial velocity that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
Answers
Answered by
bobpursley
Is there a question in this?
Answered by
Anonymous
The questions is x component of the vector?
Answered by
Dom
First set up your cartesian coordinate system. You find that the "magnitude" of the velocity vector is the hypotenuse of your newly formed right triangle. Use trigonometric functions (sin,cos,tan) to find this x-component of the vector.
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