Consider a particle with initial velocity that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

Question

Consider a particle with initial velocity  that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

bobpursley · Answer

Is there a question in this?

Anonymous · Answer

The questions is x component of the vector?

Dom · Answer

First set up your cartesian coordinate system. You find that the "magnitude" of the velocity vector is the hypotenuse of your newly formed right triangle. Use trigonometric functions (sin,cos,tan) to find this x-component of the vector.