Asked by tod

Consider a particle with initial velocity that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

Answers

Answered by bobpursley
Is there a question in this?
Answered by Anonymous
The questions is x component of the vector?
Answered by Dom
First set up your cartesian coordinate system. You find that the "magnitude" of the velocity vector is the hypotenuse of your newly formed right triangle. Use trigonometric functions (sin,cos,tan) to find this x-component of the vector.
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