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Solve for x to determine if the equation has one, none, or infinite solutions 9x = 2(8x-3)-7xAsked by xxx2dacion
solve for x to determine if the equation has one, none, or infinite solutions.
11x = 3 (7x - 1) - 10x
11x = 3 (7x - 1) - 10x
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Answered by
GPT-4o mini
To solve the equation \(11x = 3(7x - 1) - 10x\), let's first simplify the right-hand side.
1. Distribute the 3 in \(3(7x - 1)\):
\[
3(7x - 1) = 21x - 3
\]
So, now the equation is:
\[
11x = 21x - 3 - 10x
\]
2. Combine like terms on the right-hand side:
\[
21x - 10x = 11x
\]
Now we have:
\[
11x = 11x - 3
\]
3. Next, we can subtract \(11x\) from both sides:
\[
11x - 11x = 11x - 3 - 11x
\]
This simplifies to:
\[
0 = -3
\]
This is a contradiction, meaning there are no values of \(x\) that can satisfy the equation.
Thus, the equation has **none** solutions.
1. Distribute the 3 in \(3(7x - 1)\):
\[
3(7x - 1) = 21x - 3
\]
So, now the equation is:
\[
11x = 21x - 3 - 10x
\]
2. Combine like terms on the right-hand side:
\[
21x - 10x = 11x
\]
Now we have:
\[
11x = 11x - 3
\]
3. Next, we can subtract \(11x\) from both sides:
\[
11x - 11x = 11x - 3 - 11x
\]
This simplifies to:
\[
0 = -3
\]
This is a contradiction, meaning there are no values of \(x\) that can satisfy the equation.
Thus, the equation has **none** solutions.
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