Question

Find the value of the function.
f(2)=

if the x intercept is (3,0)
and there is no y intercept

Answer 1

Given that the x-intercept of the function \( f(x) \) is at the point \( (3, 0) \), this means that when \( x = 3 \), the function value \( f(3) = 0 \).

The fact that there is no y-intercept implies that the function is possibly vertical or undefined at \( x = 0 \). However, since we are asked to find \( f(2) \), we will consider a possible linear function that meets the given conditions:

Let's assume a linear function in the form of \( f(x) = m(x - 3) \), where \( m \) is some non-zero slope. We know that the function should not cross the y-axis (i.e., the function is not defined at \( x = 0 \)).

To ensure there is no y-intercept, we can set the function to be undefined or not applicable at \( x = 0 \). One example could be to restrict the domain, but let's work with a function that's undefined at \( x = 0 \).

For example, if we consider the function \( f(x) = k(x - 3) \) where \( \text{if } x < 0 \text{ then } f(x) \text{ is undefined or specified.} \)

To calculate:
- Find \( f(2) \):
\[
f(2) = k(2 - 3) = k(-1) = -k
\]

However, without knowing the specific value of \( k \), we can't provide the exact value of \( f(2) \). Nonetheless, we’ve determined that the function approaches this value based on \( k \).

Thus, if you have a specific value for \( k \) or if there are more conditions given, we could compute \( f(2) \) accurately.

But for our current assessment, \( f(2) = -k \), where \( k \) is a constant that defines the function further based on its orientation.