Use the image to answer the question.

A coordinate plane with four quadrants showsthe x-axis ranging from negative 4 to 12 in increments of 1 and the y-axis from 1 to negative 16 in increments of 1. Points upper A, upper B, upper A prime, and upper B prime are plotted on quadrant 4. The plotted points are as follows: Upper A is left parenthesis 1 comma negative 3 right parenthesis and upper B is left parenthesis 2 comma negative 4 right parenthesis. The points are joined by a line. Upper A prime is plotted as left parenthesis 4 comma negative 12 right parenthesis and upper B prime as left parenthesis 8 comma negative 16 right parenthesis. The points are joined by a line.

Determine the scale factor used in the dilation of line segment AB
, centered at the origin.

(1 point)
Responses

4
4

2
2

14
Start Fraction 1 over 4 End Fraction

−4
negative 4
Skip to navigation

1 answer

To determine the scale factor used in the dilation of the line segment \( AB \) (from points \( A(1, -3) \) to \( B(2, -4) \)) to its corresponding points \( A'(4, -12) \) and \( B'(8, -16) \), we can analyze the coordinates.

Step 1: Calculate the lengths of the segments

Length of Segment \( AB \): Using the distance formula between points \( A(x_1, y_1) \) and \( B(x_2, y_2) \): \[ d_{AB} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} = \sqrt{(2 - 1)^2 + (-4 + 3)^2} = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2} \]

Length of Segment \( A'B' \): Now, calculate the distance for points \( A'(4, -12) \) and \( B'(8, -16) \): \[ d_{A'B'} = \sqrt{(8 - 4)^2 + (-16 + 12)^2} = \sqrt{(4)^2 + (-4)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \]

Step 2: Determine the scale factor

The scale factor \( k \) is the ratio of the lengths of the segments: \[ k = \frac{d_{A'B'}}{d_{AB}} = \frac{4\sqrt{2}}{\sqrt{2}} = 4 \]

Thus, the scale factor used in the dilation of line segment \( AB \), centered at the origin, is 4.

Final Answer:

4