Rita has a circular hot tub. The hot tub has a diameter of 10 feet. It is 3.5 feet deep. How much water can the hot tub hold?(1 point)


cubic feet

1 answer

To determine how much water the hot tub can hold, we need to calculate the volume of the cylindrical shape of the hot tub. The formula for the volume \( V \) of a cylinder is given by:

\[ V = \pi r^2 h \]

where:

  • \( r \) is the radius of the base of the cylinder,
  • \( h \) is the height (or depth, in this case) of the cylinder,
  • \( \pi \) is approximately 3.14159.

Given that the diameter of the hot tub is 10 feet, we can find the radius \( r \):

\[ r = \frac{diameter}{2} = \frac{10 \text{ feet}}{2} = 5 \text{ feet} \]

The depth \( h \) of the hot tub is given as 3.5 feet. Now, we can substitute the values into the volume formula.

\[ V = \pi (5 \text{ feet})^2 (3.5 \text{ feet}) \] \[ V = \pi (25 \text{ square feet}) (3.5 \text{ feet}) \] \[ V = \pi (87.5 \text{ cubic feet}) \]

Now, using \( \pi \approx 3.14159 \):

\[ V \approx 3.14159 \times 87.5 \approx 274.067 \text{ cubic feet} \]

Therefore, the hot tub can hold approximately 274.07 cubic feet of water.