Ask a New Question
Menu

multiply x 2 )( 3x 4 using the foil method. is it a (x-2)(3x)+(3x)(4)

(x)(3x)+4(x)+3x+4
(x)(3x+4)+(x-2)
((x-2)(3x)+(x-2)(4)

1 answer

To multiply \( (x - 2)(3x + 4) \) using the FOIL method, we use the following steps:

  1. First: Multiply the first terms of each binomial: \[ x \cdot 3x = 3x^2 \]

  2. Outer: Multiply the outer terms of the binomials: \[ x \cdot 4 = 4x \]

  3. Inner: Multiply the inner terms of the binomials: \[ -2 \cdot 3x = -6x \]

  4. Last: Multiply the last terms of each binomial: \[ -2 \cdot 4 = -8 \]

Now, combine all these results: \[ 3x^2 + 4x - 6x - 8 \]

Combining like terms gives: \[ 3x^2 - 2x - 8 \]

So the final result of multiplying \( (x - 2)(3x + 4) \) using the FOIL method is: \[ 3x^2 - 2x - 8 \]

Based on your provided choices, the correct option corresponding to FOIL multiplication is \((x-2)(3x)+(x-2)(4)\), as this illustrates the concept of distributing each term in the first binomial to each term in the second binomial.