To multiply the expressions \( (x + 2)(3x + 4) \) using the FOIL method, follow these steps:
FOIL stands for:
- First
- Outer
- Inner
- Last
-
First: Multiply the first terms in each binomial: \[ x \cdot 3x = 3x^2 \]
-
Outer: Multiply the outer terms in the expression: \[ x \cdot 4 = 4x \]
-
Inner: Multiply the inner terms: \[ 2 \cdot 3x = 6x \]
-
Last: Multiply the last terms in each binomial: \[ 2 \cdot 4 = 8 \]
Now, combine all these results: \[ 3x^2 + 4x + 6x + 8 \]
Combine the like terms (4x + 6x): \[ 3x^2 + 10x + 8 \]
So, the final result of multiplying \( (x + 2)(3x + 4) \) is: \[ \boxed{3x^2 + 10x + 8} \]