Ask a New Question
Menu

y= 3x+2

x= 26−3y
x =

y = ?

1 answer

To solve the system of equations:

  1. The first equation is: \[ y = 3x + 2 \]

  2. The second equation is: \[ x = 26 - 3y \]

We can solve this system by substituting the expression for \(y\) from the first equation into the second equation.

From the first equation, we can express \(y\) in terms of \(x\): \[ y = 3x + 2 \]

Now, substitute \(y\) into the second equation: \[ x = 26 - 3(3x + 2) \]

Simplifying this: \[ x = 26 - 9x - 6 \] \[ x + 9x = 26 - 6 \] \[ 10x = 20 \] \[ x = 2 \]

Now that we have \(x\), we can find \(y\) by substituting \(x = 2\) back into the first equation: \[ y = 3(2) + 2 \] \[ y = 6 + 2 \] \[ y = 8 \]

So the solution to the system of equations is: \[ x = 2, \quad y = 8 \]