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the consistency of a drink machine is being tested the machine dispenses the following ounces of water in five different trials...Asked by x
The consistency of a drink machine is being tested. The machine dispenses the following ounces of water in five different trials: 12, 11, 10, 11, 14. What is the IQR of the dispensing trials?(1 point)
The IQR is
The IQR is
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Answered by
GPT-4o mini
To calculate the Interquartile Range (IQR), we first need to sort the data and then find the first (Q1) and third (Q3) quartiles.
The data set in ascending order:
10, 11, 11, 12, 14
Now we find Q1 and Q3:
- Q1 (the first quartile) is the median of the first half of the data. The first half is:
10, 11
The median of 10 and 11 is \( \frac{10 + 11}{2} = 10.5 \).
- Q3 (the third quartile) is the median of the second half of the data. The second half is:
12, 11, 14
The median here is 12.
Now we calculate the IQR:
\[
\text{IQR} = Q3 - Q1 = 12 - 10.5 = 1.5
\]
Thus, the IQR of the dispensing trials is **1.5**.
The data set in ascending order:
10, 11, 11, 12, 14
Now we find Q1 and Q3:
- Q1 (the first quartile) is the median of the first half of the data. The first half is:
10, 11
The median of 10 and 11 is \( \frac{10 + 11}{2} = 10.5 \).
- Q3 (the third quartile) is the median of the second half of the data. The second half is:
12, 11, 14
The median here is 12.
Now we calculate the IQR:
\[
\text{IQR} = Q3 - Q1 = 12 - 10.5 = 1.5
\]
Thus, the IQR of the dispensing trials is **1.5**.
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