To compare the functions \( f(x) = 8x \) and \( g(x) = \log_8(x) \), we’ll first evaluate \( g(x) \) at the points provided in the answer choices.
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For \( x = 1 \):
- \( g(1) = \log_8(1) = 0 \) (because \( 8^0 = 1 \))
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For \( x = -1 \):
- The logarithm \( \log_8(-1) \) is not defined in the real number system, so this point cannot be evaluated.
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For \( x = 8 \):
- \( g(8) = \log_8(8) = 1 \) (because \( 8^1 = 8 \))
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For \( x = 0.125 \):
- \( g(0.125) = \log_8(0.125) = \log_8\left(\frac{1}{8}\right) = -1 \) (because \( 8^{-1} = 0.125 \))
Now let's review the answer choices based on these evaluations:
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(1, 8) and (−1, 0.125): These points correspond to \( f(x) \), not \( g(x) \) (and \(-1\) is not valid).
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(−1,−8) and (1,−0.125): Both points are invalid for \( g(x) \); \(-1\) is not a valid input for log function, and neither of them relates to what \( g(x) \) provides.
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(1, 0.125) and (−1, 8): \( g(1) = 0 \), so this pair includes an invalid point from the logarithm perspective.
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(8, 1) and (0.125, −1): Here we get valid points: \( g(8) = 1 \) and \( g(0.125) = -1 \).
Hence, the correct choice that contains two points on the graph of \( g(x) = \log_8(x) \) is: (8, 1) and (0.125, −1).