To calculate the mass of the iron block, you can use the formula:
\[ \text{Mass} = \text{Volume} \times \text{Density} \]
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Calculate the volume of the block: The volume \( V \) of a rectangular prism (block) is calculated as:
\[ V = \text{length} \times \text{width} \times \text{height} \]
Given:
- Length = 8 cm = 0.08 m (you need to convert cm to m)
- Width = 5 cm = 0.05 m
- Height = 4 cm = 0.04 m
Now calculate the volume in cubic meters:
\[ V = 0.08 , \text{m} \times 0.05 , \text{m} \times 0.04 , \text{m} = 0.00016 , \text{m}^3 \]
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Use the density to find the mass: Given the density of iron is 7,874 kg/m³:
\[ \text{Mass} = 0.00016 , \text{m}^3 \times 7,874 , \text{kg/m}^3 = 1.2624 , \text{kg} \]
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Convert kilograms to grams: To convert kilograms to grams, multiply by 1,000:
\[ 1.2624 , \text{kg} \times 1,000 , \text{g/kg} = 1,262.4 , \text{g} \]
Now to summarize, the mass of the iron block is approximately 1,262.4 g. Since the options provided were:
- 1,259,840 g
- 49.2125 g
- 1,259.84 g
- 0.49 g
None of the options exactly match the calculated mass. However, the closest option provided is 1,259.84 g.
Therefore, the correct response is:
1,259.84 g.