Use the image to answer the question.

An illustration shows a triangular prism. The front triangular face is visible. The right rectangular face is visible. The visible rectangular face has a width of 5 centimeters and length of 11 centimeters. The sides and edges that are not visible are indicated by dashed lines. The legs of the triangular face are labeled 3 centimeters and 4 centimeters. The hypotenuse shares the same label as the width of the visible rectangular face.

What is the surface area of the triangular prism?
?square centimeters

1 answer

To find the surface area of the triangular prism, we first need to calculate the area of the triangular face and the areas of the rectangular faces.

Step 1: Area of the Triangular Face

The triangular face is a right triangle with legs of 3 cm and 4 cm. The area \( A \) of a triangle is given by the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, we can take the legs of the triangle as the base and height: \[ A = \frac{1}{2} \times 3 \text{ cm} \times 4 \text{ cm} = \frac{1}{2} \times 12 \text{ cm}^2 = 6 \text{ cm}^2 \]

Step 2: Area of the Rectangular Faces

The prism has three rectangular faces:

  1. The visible rectangular face

  2. The opposite rectangular face (not visible)

  3. The rectangular face that connects the two triangular faces.

  4. The visible rectangular face has a width of 5 cm and a length of 11 cm: \[ \text{Area}_{\text{visible}} = \text{width} \times \text{length} = 5 \text{ cm} \times 11 \text{ cm} = 55 \text{ cm}^2 \]

  5. The opposite rectangular face will have the same dimensions, so: \[ \text{Area}_{\text{opposite}} = 55 \text{ cm}^2 \]

  6. The connecting rectangular face has a width equal to the hypotenuse of the triangle. To find the hypotenuse \( c \), we can use the Pythagorean theorem: \[ c = \sqrt{(3 \text{ cm})^2 + (4 \text{ cm})^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \text{ cm} \] Now this rectangular face will have a width of 5 cm and a length equal to the length of the prism (which is given as 11 cm): \[ \text{Area}_{\text{connecting}} = \text{width} \times \text{length} = 5 \text{ cm} \times 11 \text{ cm} = 55 \text{ cm}^2 \]

Step 3: Total Surface Area

Now we sum the areas of all the faces:

  1. Area of two triangular faces (since there are two identical triangular faces): \[ 2 \times 6 \text{ cm}^2 = 12 \text{ cm}^2 \]

  2. Area of the three rectangular faces: \[ \text{Area}{\text{visible}} + \text{Area}{\text{opposite}} + \text{Area}_{\text{connecting}} = 55 \text{ cm}^2 + 55 \text{ cm}^2 + 55 \text{ cm}^2 = 165 \text{ cm}^2 \]

Final Calculation of Total Surface Area

\[ \text{Total Surface Area} = \text{Area}{\text{triangles}} + \text{Area}{\text{rectangles}} = 12 \text{ cm}^2 + 165 \text{ cm}^2 = 177 \text{ cm}^2 \]

Conclusion

The total surface area of the triangular prism is: \[ \boxed{177} \text{ square centimeters} \]