To determine the smallest discrepancy between the experimental and expected probabilities based on Jade's experiment, we need to follow these steps:
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Calculate the Total Number of Tosses: Add up the frequencies of each outcome: \[ 10 + 9 + 6 + 15 + 13 + 8 = 61 \]
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Calculate the Expected Probability for Each Outcome: For a fair die with the numbers 2, 4, 6, 8, 10, and 12, the expected probability for each outcome is: \[ P_{\text{expected}} = \frac{1}{6} \quad \text{(since there are 6 outcomes)} \]
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Calculate the Experimental Probability for Each Outcome: The experimental probability for each outcome is given by the frequency of each outcome divided by the total number of tosses (61): \[ P_{\text{experimental}}(2) = \frac{10}{61} \approx 0.164 \] \[ P_{\text{experimental}}(4) = \frac{9}{61} \approx 0.148 \] \[ P_{\text{experimental}}(6) = \frac{6}{61} \approx 0.098 \] \[ P_{\text{experimental}}(8) = \frac{15}{61} \approx 0.246 \] \[ P_{\text{experimental}}(10) = \frac{13}{61} \approx 0.213 \] \[ P_{\text{experimental}}(12) = \frac{8}{61} \approx 0.131 \]
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Calculate the Discrepancy for Each Outcome: The discrepancy is calculated as the absolute difference between the experimental probability and expected probability: \[ \text{Discrepancy for } 2: \left| \frac{10}{61} - \frac{1}{6} \right| \approx \left| 0.164 - 0.167 \right| \approx 0.003 \] \[ \text{Discrepancy for } 4: \left| \frac{9}{61} - \frac{1}{6} \right| \approx \left| 0.148 - 0.167 \right| \approx 0.019 \] \[ \text{Discrepancy for } 6: \left| \frac{6}{61} - \frac{1}{6} \right| \approx \left| 0.098 - 0.167 \right| \approx 0.069 \] \[ \text{Discrepancy for } 8: \left| \frac{15}{61} - \frac{1}{6} \right| \approx \left| 0.246 - 0.167 \right| \approx 0.079 \] \[ \text{Discrepancy for } 10: \left| \frac{13}{61} - \frac{1}{6} \right| \approx \left| 0.213 - 0.167 \right| \approx 0.046 \] \[ \text{Discrepancy for } 12: \left| \frac{8}{61} - \frac{1}{6} \right| \approx \left| 0.131 - 0.167 \right| \approx 0.036 \]
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Find the Smallest Discrepancy: The smallest discrepancy found is for the outcome of 2, which is approximately 0.003.
Thus, the smallest discrepancy between the experimental and expected probability of this experiment is \(\boxed{0.003}\).