Question
Which of the following percentages accurately estimates the area under a normal curve between a z-score of −0.11
and 2.43?(1 point)
Responses
99.25 percent
99.25 percent
53.63 percent
53.63 percent
45.62 percent
45.62 percent
54.38 percent
and 2.43?(1 point)
Responses
99.25 percent
99.25 percent
53.63 percent
53.63 percent
45.62 percent
45.62 percent
54.38 percent
Answers
GPT-4o mini
To find the area under a normal curve between a z-score of -0.11 and 2.43, we can look up the cumulative probabilities for these two z-scores using a standard normal distribution table or a calculator.
1. **For \( z = -0.11 \)**: the cumulative probability (area to the left) is approximately \( 0.4562 \) or \( 45.62\% \).
2. **For \( z = 2.43 \)**: the cumulative probability (area to the left) is approximately \( 0.9925 \) or \( 99.25\% \).
To find the area between these two z-scores, we subtract the cumulative probability at -0.11 from the cumulative probability at 2.43:
\[
\text{Area between } z = -0.11 \text{ and } z = 2.43 = P(Z < 2.43) - P(Z < -0.11)
\]
\[
= 0.9925 - 0.4562 = 0.5363
\]
Converting this to a percentage gives:
\[
0.5363 \times 100 = 53.63\%
\]
Thus, the area under the normal curve between a z-score of -0.11 and 2.43 is approximately **53.63 percent**.
So the correct response is:
**53.63 percent**
1. **For \( z = -0.11 \)**: the cumulative probability (area to the left) is approximately \( 0.4562 \) or \( 45.62\% \).
2. **For \( z = 2.43 \)**: the cumulative probability (area to the left) is approximately \( 0.9925 \) or \( 99.25\% \).
To find the area between these two z-scores, we subtract the cumulative probability at -0.11 from the cumulative probability at 2.43:
\[
\text{Area between } z = -0.11 \text{ and } z = 2.43 = P(Z < 2.43) - P(Z < -0.11)
\]
\[
= 0.9925 - 0.4562 = 0.5363
\]
Converting this to a percentage gives:
\[
0.5363 \times 100 = 53.63\%
\]
Thus, the area under the normal curve between a z-score of -0.11 and 2.43 is approximately **53.63 percent**.
So the correct response is:
**53.63 percent**