Use the image to answer the question.

An illustration shows two triangles, one big and one small. In the small triangle, one side measures 11.4 inches and another side measures 18 inches. In the big triangle, the side corresponding to 11.4 inches in the small triangle measures x and the side corresponding to 18 inches measures 23.4 inches.

What is the length of x in decimal form to the nearest hundredth?

(1 point)
inches

1 answer

To find the length of \( x \) in the big triangle, we can use the concept of similar triangles. The sides of similar triangles are proportional. Therefore, we can set up a proportion based on the corresponding sides of the small triangle and the big triangle.

In the small triangle:

  • One side measures \( 11.4 \) inches.
  • Another side measures \( 18 \) inches.

In the big triangle:

  • The side corresponding to \( 11.4 \) inches is \( x \).
  • The side corresponding to \( 18 \) inches is \( 23.4 \) inches.

We can set up the following proportion:

\[ \frac{x}{11.4} = \frac{23.4}{18} \]

Now we will solve for \( x \). First, cross-multiply:

\[ x \cdot 18 = 11.4 \cdot 23.4 \]

Calculating \( 11.4 \cdot 23.4 \):

\[ 11.4 \cdot 23.4 = 267.96 \]

Now the equation becomes:

\[ 18x = 267.96 \]

Next, divide both sides by \( 18 \):

\[ x = \frac{267.96}{18} \]

Calculating \( \frac{267.96}{18} \):

\[ x \approx 14.88 \]

Thus, the length of \( x \) in decimal form to the nearest hundredth is:

\[ \boxed{14.88} \text{ inches} \]