To calculate the volume of a cylindrical gas tank, we can use the formula:
\[ V = \pi r^2 h \]
where \(V\) is the volume, \(r\) is the radius of the circular base, and \(h\) is the height of the cylinder.
From the problem, the width of the tank is given as 6 feet. The radius \(r\) is half of the width:
\[ r = \frac{6}{2} = 3 \text{ feet} \]
The height \(h\) of the tank is given as 8 feet.
Now, substituting the values into the volume formula:
\[ V = \pi (3)^2 (8) \]
Calculating \(3^2\):
\[ 3^2 = 9 \]
Now substitute back into the formula:
\[ V = \pi \cdot 9 \cdot 8 \]
Calculating \(9 \cdot 8\):
\[ 9 \cdot 8 = 72 \]
Now substituting in \( \pi \) as 3.14:
\[ V = 3.14 \cdot 72 \]
Now calculate \(3.14 \cdot 72\):
\[ 3.14 \cdot 72 = 226.08 \]
Thus, the volume of the gas tank is:
\[ \boxed{226.08} \text{ cubic feet} \]