To find the volume \( V \) of a cylinder, we use the formula:
\[ V = \pi r^2 h \]
where \( r \) is the radius and \( h \) is the height. In this case, the height \( h \) is 6 inches and the radius \( r \) is 3 inches.
Using \( \pi \approx 3.14 \):
- Calculate the area of the base:
\[ r^2 = 3^2 = 9 \]
- Then, calculate the volume:
\[ V = 3.14 \times 9 \times 6 \]
Calculating \( 9 \times 6 \):
\[ 9 \times 6 = 54 \]
Now, substituting this back into the volume equation:
\[ V = 3.14 \times 54 \]
Calculating \( 3.14 \times 54 \):
\[ 3.14 \times 54 = 169.56 \]
Thus, the volume of the can is:
\[ \boxed{169.56} \text{ cubic inches} \]