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use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2 inches. Use 3.14 as an...Question
Use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2inches. Use 3.14 as an approximation for pi and round your answer to the nearest hundredth, if necessary.
1,222.54
407.51
3,260.11
115.55
1,222.54
407.51
3,260.11
115.55
Answers
GPT-4o mini
The formula for the volume \( V \) of a sphere is given by:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
First, we need to find the radius of the basketball. The diameter is given as 9.2 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{9.2}{2} = 4.6 \text{ inches}
\]
Now we can plug the radius into the volume formula using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (4.6)^3
\]
Calculating \( (4.6)^3 \):
\[
(4.6)^3 = 4.6 \times 4.6 \times 4.6 = 97.336
\]
Now, substituting this back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 97.336
\]
Calculating \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18667
\]
Now multiply this by 97.336:
\[
V \approx 4.18667 \times 97.336 \approx 407.515
\]
Rounding to the nearest hundredth, we find:
\[
V \approx 407.51
\]
Therefore, the volume of the basketball is **407.51 cubic inches**, so the correct option is **407.51**.
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
First, we need to find the radius of the basketball. The diameter is given as 9.2 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{9.2}{2} = 4.6 \text{ inches}
\]
Now we can plug the radius into the volume formula using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (4.6)^3
\]
Calculating \( (4.6)^3 \):
\[
(4.6)^3 = 4.6 \times 4.6 \times 4.6 = 97.336
\]
Now, substituting this back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 97.336
\]
Calculating \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18667
\]
Now multiply this by 97.336:
\[
V \approx 4.18667 \times 97.336 \approx 407.515
\]
Rounding to the nearest hundredth, we find:
\[
V \approx 407.51
\]
Therefore, the volume of the basketball is **407.51 cubic inches**, so the correct option is **407.51**.