To find the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.
From your input, the height \( h \) is given as 19, but it's unclear what "Length 11" refers to. Since a cone has a radius \( r \) at the base, I will assume that "Length 11" refers to the diameter of the base of the cone.
To find the radius \( r \), you can divide the diameter by 2:
\[ r = \frac{d}{2} = \frac{11}{2} = 5.5 \]
Now that we have the radius and height, we can plug these values into the volume formula:
\[ V = \frac{1}{3} \pi (5.5)^2 (19) \]
Calculating \( (5.5)^2 \):
\[ (5.5)^2 = 30.25 \]
Now substitute this back into the volume formula:
\[ V = \frac{1}{3} \pi (30.25) (19) \]
Next, calculate \( 30.25 \times 19 \):
\[ 30.25 \times 19 = 574.75 \]
Now substitute into the formula:
\[ V = \frac{1}{3} \pi (574.75) \]
Now using \( \pi \approx 3.14 \):
\[ V \approx \frac{1}{3} (3.14) (574.75) \]
First calculate \( 3.14 \times 574.75 \):
\[ 3.14 \times 574.75 \approx 1805.4225 \]
Then divide by 3:
\[ V \approx \frac{1805.4225}{3} \approx 601.8075 \]
Finally, rounding to the nearest hundredth:
\[ V \approx 601.81 \text{ cubic millimeters} \]
So the volume of the cone is approximately 601.81 cubic millimeters.