Asked by Billy bob
Four students rode different buses to school, and each trip took 30 min.
One student rode 8 mi, one rode 10 mi, and the other two each rode 12 mi . What was the average speed of the buses? (1
One student rode 8 mi, one rode 10 mi, and the other two each rode 12 mi . What was the average speed of the buses? (1
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the average speed of the buses, we can use the formula for speed:
\[
\text{Speed} = \frac{\text{Distance}}{\text{Time}}
\]
In this case, we need to calculate the average speed for each of the buses used by the four students. Each trip took 30 minutes, which we can convert to hours:
\[
30 \text{ minutes} = \frac{30}{60} = 0.5 \text{ hours}
\]
Next, we will calculate the speeds for each student based on their distances.
1. Student who rode 8 miles:
\[
\text{Speed} = \frac{8 \text{ miles}}{0.5 \text{ hours}} = 16 \text{ miles per hour}
\]
2. Student who rode 10 miles:
\[
\text{Speed} = \frac{10 \text{ miles}}{0.5 \text{ hours}} = 20 \text{ miles per hour}
\]
3. Student who rode 12 miles (first):
\[
\text{Speed} = \frac{12 \text{ miles}}{0.5 \text{ hours}} = 24 \text{ miles per hour}
\]
4. Student who rode 12 miles (second):
\[
\text{Speed} = \frac{12 \text{ miles}}{0.5 \text{ hours}} = 24 \text{ miles per hour}
\]
Now, we have the speeds of the four students:
- 16 mph
- 20 mph
- 24 mph
- 24 mph
To calculate the average speed of the buses, we need to find the average of these speeds:
\[
\text{Average Speed} = \frac{\text{Total Speed}}{\text{Number of Students}} = \frac{16 + 20 + 24 + 24}{4}
\]
Calculating the total speed:
\[
16 + 20 + 24 + 24 = 84
\]
Now, divide by the number of students:
\[
\text{Average Speed} = \frac{84}{4} = 21 \text{ miles per hour}
\]
So, the average speed of the buses was **21 miles per hour**.
\[
\text{Speed} = \frac{\text{Distance}}{\text{Time}}
\]
In this case, we need to calculate the average speed for each of the buses used by the four students. Each trip took 30 minutes, which we can convert to hours:
\[
30 \text{ minutes} = \frac{30}{60} = 0.5 \text{ hours}
\]
Next, we will calculate the speeds for each student based on their distances.
1. Student who rode 8 miles:
\[
\text{Speed} = \frac{8 \text{ miles}}{0.5 \text{ hours}} = 16 \text{ miles per hour}
\]
2. Student who rode 10 miles:
\[
\text{Speed} = \frac{10 \text{ miles}}{0.5 \text{ hours}} = 20 \text{ miles per hour}
\]
3. Student who rode 12 miles (first):
\[
\text{Speed} = \frac{12 \text{ miles}}{0.5 \text{ hours}} = 24 \text{ miles per hour}
\]
4. Student who rode 12 miles (second):
\[
\text{Speed} = \frac{12 \text{ miles}}{0.5 \text{ hours}} = 24 \text{ miles per hour}
\]
Now, we have the speeds of the four students:
- 16 mph
- 20 mph
- 24 mph
- 24 mph
To calculate the average speed of the buses, we need to find the average of these speeds:
\[
\text{Average Speed} = \frac{\text{Total Speed}}{\text{Number of Students}} = \frac{16 + 20 + 24 + 24}{4}
\]
Calculating the total speed:
\[
16 + 20 + 24 + 24 = 84
\]
Now, divide by the number of students:
\[
\text{Average Speed} = \frac{84}{4} = 21 \text{ miles per hour}
\]
So, the average speed of the buses was **21 miles per hour**.
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