Question
Question 1 A)Which analogy best describes voltage?(1 point) Responses diameter of a pipe through which water move diameter of a pipe through which water move pressure of water moving through a pipe pressure of water moving through a pipe turbine or mill inserted into a flow of water turbine or mill inserted into a flow of water length of the pipe through which water moves length of the pipe through which water moves Question 2 A)Which analogy best describes amperage?(1 point) Responses turbine or mill inserted into a flow of water turbine or mill inserted into a flow of water length of the pipe through which water moves length of the pipe through which water moves pressure of water moving through a pipe pressure of water moving through a pipe diameter of a pipe through which water moves diameter of a pipe through which water moves Question 3 A)Which analogy best describes resistance?(1 point) Responses turbine or mill inserted into a flow of water turbine or mill inserted into a flow of water diameter of a pipe through which water moves diameter of a pipe through which water moves pressure of water moving through a pipe pressure of water moving through a pipe length of the pipe through which water moves length of the pipe through which water moves Question 4 A) The current in a circuit is halved. What happens to the resistance? V=IR (1 point) Responses The resistance stays the same. The resistance stays the same. The resistance is doubled. The resistance is doubled. The resistance is tripled. The resistance is tripled. The resistance is halved. The resistance is halved. Question 5 A) A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit? V=IR (1 point) Responses 0.4 A 0.4 A 0.625 A 0.625 A 2.5 A 2.5 A 14.4 A 14.4 A
Answers
GPT-4o mini
Here are the answers to your questions:
**Question 1:**
A) Which analogy best describes voltage?
**Response:** pressure of water moving through a pipe
**Question 2:**
A) Which analogy best describes amperage?
**Response:** diameter of a pipe through which water moves
**Question 3:**
A) Which analogy best describes resistance?
**Response:** length of the pipe through which water moves
**Question 4:**
A) The current in a circuit is halved. What happens to the resistance? V=IR
**Response:** The resistance stays the same.
(Note: According to Ohm's law, if voltage remains constant and current is halved, resistance must effectively double, but if you are viewing resistance in relation to a variable circuit where only current changes, the best option can reflect conditional clarity in some interpretations.)
**Question 5:**
A) A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit? V=IR
1. The total voltage (V) from the batteries: \( 4 \times 1.5 = 6 \) volts.
2. Using Ohm's law \( I = \frac{V}{R} \):
\( I = \frac{6 \text{ volts}}{2.4 \text{ ohms}} = 2.5 \) A
**Response:** 2.5 A
If you have any further questions or need additional explanations, feel free to ask!
**Question 1:**
A) Which analogy best describes voltage?
**Response:** pressure of water moving through a pipe
**Question 2:**
A) Which analogy best describes amperage?
**Response:** diameter of a pipe through which water moves
**Question 3:**
A) Which analogy best describes resistance?
**Response:** length of the pipe through which water moves
**Question 4:**
A) The current in a circuit is halved. What happens to the resistance? V=IR
**Response:** The resistance stays the same.
(Note: According to Ohm's law, if voltage remains constant and current is halved, resistance must effectively double, but if you are viewing resistance in relation to a variable circuit where only current changes, the best option can reflect conditional clarity in some interpretations.)
**Question 5:**
A) A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit? V=IR
1. The total voltage (V) from the batteries: \( 4 \times 1.5 = 6 \) volts.
2. Using Ohm's law \( I = \frac{V}{R} \):
\( I = \frac{6 \text{ volts}}{2.4 \text{ ohms}} = 2.5 \) A
**Response:** 2.5 A
If you have any further questions or need additional explanations, feel free to ask!