The best player on a basketball team makes 70​% of all free throws. The​ second-best player makes 65​% of all free throws. The​ third-best player makes 60​% of all free throws. Based on their experimental​ probabilities, estimate the number of free throws each player will make in his or her next 60 attempts. Explain.

Question

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Part 1
For the best​ player, one equation that gives the estimated number of free throws is
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StartFraction 70 Over 100 EndFraction equals x.
StartFraction 70 Over 100 EndFraction equals StartFraction x Over 60 EndFraction .
StartFraction 70 Over 100 EndFraction equals StartFraction 1 Over x EndFraction .
StartFraction 70 Over 100 EndFraction equals StartFraction 60 Over x EndFraction .
The best player will make about
  
enter your response here free throws.

Answer 1

To estimate the number of free throws the best player will make in their next 60 attempts, you can use the equation:

\[ \frac{70}{100} = \frac{x}{60} \]

where \( x \) is the number of successful free throws made by the player.

To solve for \( x \), you can cross-multiply:

\[ 70 \times 60 = 100 \times x \]

This simplifies to:

\[ 4200 = 100x \]

Now, divide both sides by 100:

\[ x = \frac{4200}{100} = 42 \]

So, the best player is expected to make about 42 free throws in their next 60 attempts.

Summary:

• The best player (70% success rate) will make approximately 42 free throws out of 60 attempts.