Question

tickets for movie A are $4. tickets for movie B are $5. The movie theater earned $200 and sold 47 tickets.
how many tickets were sold for movie A?

Answer 1

Let \( x \) be the number of tickets sold for movie A, and let \( y \) be the number of tickets sold for movie B.

We have the following two equations based on the problem statement:

1. \( x + y = 47 \) (the total number of tickets sold)
2. \( 4x + 5y = 200 \) (the total earnings from ticket sales)

Now, we can solve these equations step by step.

From the first equation, we can express \( y \) in terms of \( x \):

\[
y = 47 - x
\]

Now, we can substitute this expression for \( y \) into the second equation:

\[
4x + 5(47 - x) = 200
\]

Expanding this gives:

\[
4x + 235 - 5x = 200
\]

Combining like terms:

\[
-1x + 235 = 200
\]

Now, we can isolate \( x \):

\[
-1x = 200 - 235
\]
\[
-1x = -35
\]
\[
x = 35
\]

Now that we have \( x \), we can find \( y \):

\[
y = 47 - x = 47 - 35 = 12
\]

Therefore, the number of tickets sold for movie A is \( \boxed{35} \).