The senior class at Hartford High School is planning their prom. They’ve narrowed the location down to two choices. The Regal Hotel charges, C

Question

, $500 for the ballroom rental fee and $75 per student, s
, for the meal. The Greenhill Country Club charges, C
, $1,000 for the ballroom rental fee and $65 per student, s
, for the meal. Create a pair of linear equations that represent this real-world problem.(1 point)
Responses

Regal Hotel: C=75s+500
; Greenhill Country Club: C=65s+1,000
Regal Hotel: upper C equals 75 s plus 500 ; Greenhill Country Club: upper C equals 65 s plus 1,000

Regal Hotel: C=1,000s+75
; Greenhill Country Club: C=500s+65
Regal Hotel: upper C equals 1,000 s plus 75 ; Greenhill Country Club: upper C equals 500 s plus 65

Regal Hotel: C=75s+1,000
; Greenhill Country Club: C=65s+500
Regal Hotel: upper C equals 75 s plus 1,000 ; Greenhill Country Club: upper C equals 65 s plus 500

Regal Hotel: C=500s+75
; Greenhill Country Club: C=1,000s+65

Answer 1

To correctly represent the costs of each location in terms of the number of students:

1. Regal Hotel charges a fixed rental fee of $500, plus $75 per student.

   • Therefore, the equation for the Regal Hotel can be expressed as: \[ C = 75s + 500 \]

2. Greenhill Country Club charges a fixed rental fee of $1,000, plus $65 per student.

   • Thus, the equation for the Greenhill Country Club can be written as: \[ C = 65s + 1000 \]

Putting these together, the appropriate pair of linear equations is:

• Regal Hotel: \( C = 75s + 500 \)
• Greenhill Country Club: \( C = 65s + 1000 \)

So the correct response from your options is:

Regal Hotel: \( C = 75s + 500 \); Greenhill Country Club: \( C = 65s + 1000 \).