Question

The sample space of an experiment is S={1, 2, 3, 4, 5} . If each outcome is equally likely to occur, which graph models the expected probability of each outcome?(1 point) Responses Image with alt text: A bar chart is titled: Probability Model for Selecting a Number from left bracket 1 comma 2 comma 3 comma 4 comma 5 right bracket. The x-axis shows outcomes and y-axis shows probability from 0 to 6 in increments of 1. Image with alt text: A bar chart is titled: Probability Model for Selecting a Number from left bracket 1 comma 2 comma 3 comma 4 comma 5 right bracket. The x-axis shows outcomes and y-axis shows probability from 0 to 0.25 in increments of 0.05. Image with alt text: A bar chart is titled: Probability Model for Selecting a Number from left bracket 1 comma 2 comma 3 comma 4 comma 5 right bracket. The x-axis shows outcomes and y-axis shows probability from 0 to 2.5 in increments of 0.5.

Answers

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Answered by GPT-4o mini
To solve this problem, we need to determine the correct graph that models the expected probability of each outcome in the sample space \( S = \{1, 2, 3, 4, 5\} \).

Since each outcome is equally likely, the probability of each outcome is given by the formula:

\[
P(X = x) = \frac{1}{n}
\]

where \( n \) is the total number of outcomes. Here, \( n = 5 \) (the numbers 1 through 5). Thus, the probability of each outcome is:

\[
P(X = x) = \frac{1}{5} = 0.2
\]

Therefore, the expected probability for each of the outcomes (1, 2, 3, 4, 5) is 0.2.

Now let's analyze the graphs:

1. **Graph 1:** Shows probabilities from 0 to 6 - this range is incorrect since the probabilities exceed 1.
2. **Graph 2:** The y-axis shows probabilities from 0 to 0.25 in increments of 0.05. This is a suitable range and appears to have values of 0.2 (which corresponds to each outcome).
3. **Graph 3:** Shows probabilities from 0 to 2.5, which again exceed 1.

Based on this analysis, **Graph 2** is the correct one that models the expected probabilities for the outcomes {1, 2, 3, 4, 5}. Each outcome shown will have a height of 0.2, representing the expected probability of each outcome occurring.

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