Question

Solving the following system of equations
3x + y = 15
X + 2y = 10

What is the value of x? Enter your answer in the box.

Answer 1

To solve the system of equations, we have:

1. \(3x + y = 15\) (Equation 1)
2. \(x + 2y = 10\) (Equation 2)

We can solve this system using the substitution or elimination methods. Here, we will use the substitution method.

From Equation 1, we can express \(y\) in terms of \(x\):

\[
y = 15 - 3x
\]

Now, we can substitute this expression for \(y\) into Equation 2:

\[
x + 2(15 - 3x) = 10
\]

Expanding this gives:

\[
x + 30 - 6x = 10
\]

Combining like terms:

\[
-5x + 30 = 10
\]

Now, isolate \(x\):

\[
-5x = 10 - 30
\]
\[
-5x = -20
\]
\[
x = \frac{-20}{-5}
\]
\[
x = 4
\]

So, the value of \(x\) is \(4\).

Thus, the final answer is:

\[
\boxed{4}
\]