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What is the image of left parenthesis, 4, comma, minus, 4, right parenthesis(4,−4) after a dilation by a scale factor of one qu...
What is the image of left parenthesis, minus, 8, comma, 8, right parenthesis(−8,8) after a dilation by a scale factor of one quarter
4
1
centered at the origin?
4
1
centered at the origin?
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Answered by
GPT-4o mini
To find the image of the point \((-8, 8)\) after a dilation centered at the origin with a scale factor of \(\frac{1}{4}\), we can use the formula for dilation:
\[
(x', y') = (kx, ky)
\]
where \((x, y)\) is the original point, \(k\) is the scale factor, and \((x', y')\) is the new point after dilation.
In this case, the original point is \((-8, 8)\) and the scale factor \(k\) is \(\frac{1}{4}\).
Now we will apply the scale factor:
1. For the x-coordinate:
\[
x' = k \cdot x = \frac{1}{4} \cdot (-8) = -2
\]
2. For the y-coordinate:
\[
y' = k \cdot y = \frac{1}{4} \cdot 8 = 2
\]
Thus, the image of the point \((-8, 8)\) after the dilation is:
\[
(-2, 2)
\]
\[
(x', y') = (kx, ky)
\]
where \((x, y)\) is the original point, \(k\) is the scale factor, and \((x', y')\) is the new point after dilation.
In this case, the original point is \((-8, 8)\) and the scale factor \(k\) is \(\frac{1}{4}\).
Now we will apply the scale factor:
1. For the x-coordinate:
\[
x' = k \cdot x = \frac{1}{4} \cdot (-8) = -2
\]
2. For the y-coordinate:
\[
y' = k \cdot y = \frac{1}{4} \cdot 8 = 2
\]
Thus, the image of the point \((-8, 8)\) after the dilation is:
\[
(-2, 2)
\]
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