Question
Question
The volume of a container measures 3,200 in.3
and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary.(1 point)
in.3
The volume of a container measures 3,200 in.3
and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary.(1 point)
in.3
Answers
GPT-4o mini
To find the amount of empty space in the container, we first need to calculate the volume of one tennis ball and then the total volume of a dozen tennis balls.
1. **Calculate the volume of one tennis ball:**
The volume \( V \) of a sphere is given by the formula:
\[
V = \frac{4}{3} \pi r^3
\]
Given that the radius \( r \) of each tennis ball is 2.5 inches, we can substitute the values into the formula.
Using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (2.5)^3
\]
First, calculate \( (2.5)^3 \):
\[
(2.5)^3 = 2.5 \times 2.5 \times 2.5 = 15.625
\]
Now plug this value back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 15.625
\]
Calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18667\ (approximately)
\]
Now multiplying by 15.625:
\[
V \approx 4.18667 \times 15.625 \approx 65.267
\]
So, the volume of one tennis ball is approximately:
\[
V \approx 65.27\ (rounding\ to\ 2\ decimal\ places)
\]
2. **Calculate the total volume of a dozen (12) tennis balls:**
\[
\text{Total Volume} = 12 \times V \approx 12 \times 65.27 \approx 783.24
\]
3. **Determine the empty space in the container:**
The total volume of the container is given as 3200 cubic inches. Therefore, the empty space is:
\[
\text{Empty Space} = \text{Volume of Container} - \text{Total Volume of Tennis Balls}
\]
\[
\text{Empty Space} = 3200 - 783.24 \approx 2416.76
\]
Rounding this to the nearest whole number gives us:
\[
\text{Empty Space} \approx 2417\ \text{in}^3
\]
Thus, the amount of empty space in the container is approximately **2417 in³**.
1. **Calculate the volume of one tennis ball:**
The volume \( V \) of a sphere is given by the formula:
\[
V = \frac{4}{3} \pi r^3
\]
Given that the radius \( r \) of each tennis ball is 2.5 inches, we can substitute the values into the formula.
Using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (2.5)^3
\]
First, calculate \( (2.5)^3 \):
\[
(2.5)^3 = 2.5 \times 2.5 \times 2.5 = 15.625
\]
Now plug this value back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 15.625
\]
Calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18667\ (approximately)
\]
Now multiplying by 15.625:
\[
V \approx 4.18667 \times 15.625 \approx 65.267
\]
So, the volume of one tennis ball is approximately:
\[
V \approx 65.27\ (rounding\ to\ 2\ decimal\ places)
\]
2. **Calculate the total volume of a dozen (12) tennis balls:**
\[
\text{Total Volume} = 12 \times V \approx 12 \times 65.27 \approx 783.24
\]
3. **Determine the empty space in the container:**
The total volume of the container is given as 3200 cubic inches. Therefore, the empty space is:
\[
\text{Empty Space} = \text{Volume of Container} - \text{Total Volume of Tennis Balls}
\]
\[
\text{Empty Space} = 3200 - 783.24 \approx 2416.76
\]
Rounding this to the nearest whole number gives us:
\[
\text{Empty Space} \approx 2417\ \text{in}^3
\]
Thus, the amount of empty space in the container is approximately **2417 in³**.