Question

Hernando is on the football team. He is headed out for practice and he wants to know the volume of his cylindrical shaped water bottle with a radius of 2.25 inches and height of 11 inches.

What is the volume of Hernando's water bottle? Use 3.14 to approximate pi (𝜋). Round your answer to the nearest tenth.



(2 points)
Responses

25.8 in3
25.8 in3

77.7 in.3
77.7 in.3

174.9 in.3
174.9 in.3

155.43 in.3
155.43 in.3
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Answer 1

To find the volume of a cylindrical water bottle, we can use the formula for the volume of a cylinder:

\[ V = \pi r^2 h \]

where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14.

Given Hernando's water bottle:
- Radius \( r = 2.25 \) inches,
- Height \( h = 11 \) inches.

Now, let's calculate the volume:

1. First, calculate \( r^2 \):
\[ r^2 = (2.25)^2 = 5.0625 \]

2. Now, plug the values into the volume formula:
\[ V = 3.14 \times 5.0625 \times 11 \]

3. Calculate \( 3.14 \times 5.0625 \):
\[ 3.14 \times 5.0625 \approx 15.86775 \]

4. Now multiply this result by 11:
\[ V \approx 15.86775 \times 11 \approx 174.54525 \]

5. Finally, round this to the nearest tenth:
\[ V \approx 174.5 \]

So, the volume of Hernando's water bottle is approximately **174.5 in³**.

Since none of the provided options match this exactly, it seems there might have been a discrepancy. However, using the calculations, the correct answer would be closest to **174.9 in³** as per the original option list. The right volume rounded to the nearest tenth based on the calculated volume would indeed support this.