To solve the equation \( 23x = 4x + 1 \), we will follow these algebraic steps:
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Isolate the variable \( x \) by moving all terms involving \( x \) to one side of the equation. We start by subtracting \( 4x \) from both sides:
\[ 23x - 4x = 4x + 1 - 4x \]
Simplifying both sides gives:
\[ 19x = 1 \]
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Divide both sides by 19 to solve for \( x \):
\[ x = \frac{1}{19} \]
Thus, the solution to the equation \( 23x = 4x + 1 \) is
\[ \boxed{\frac{1}{19}} \]
Verification: To ensure the solution is correct, substitute \( x = \frac{1}{19} \) back into the original equation:
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Left side:
\[ 23\left(\frac{1}{19}\right) = \frac{23}{19} \]
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Right side:
\[ 4\left(\frac{1}{19}\right) + 1 = \frac{4}{19} + 1 = \frac{4}{19} + \frac{19}{19} = \frac{23}{19} \]
Since both sides equal \( \frac{23}{19} \), our solution is verified.
The final answer remains:
\[ \boxed{\frac{1}{19}} \]