Asked by wilson

Factor:
20+22v-12v^2

Answers

Answered by Henry
-12V^2 + 22V + 20.
Factor using AC Method:
2(-6V^2 + 11V + 10),
A * C = -60 = -4 * 15,
2(-6V^2 + (-4V + 15V) + 10,
Group the 4 terms into 2 factorable
pairs:

2((-6V^2 + 15V) + (-4V + 10))
2(3V(-2V + 5) + 2(-2V + 5)),
2(-2V + 5) (3V + 2)
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