To calculate the volume of the iron block, you can use the formula:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
Given that the mass of the iron block is 16,000 kg and the density of iron is 7,874 kg/m³, we can substitute these values into the formula:
\[ \text{Volume} = \frac{16,000 , \text{kg}}{7,874 , \text{kg/m}^3} \]
Now, performing the calculation:
\[ \text{Volume} \approx \frac{16,000}{7,874} \approx 2.03 , \text{m}^3 \]
Thus, the correct answer is:
2.03 m³ (2.03 m cubed).