Asked by IT'S ME
Question Which car has the greatest efficiency?(1 point) Responses a 1,200 kg car that travels 15 km per liter of fuel a 1,200 kg car that travels 15 km per liter of fuel a 1,200 kg car that travels 20 km per liter of fuel a 1,200 kg car that travels 20 km per liter of fuel a 900 kg car that travels 15 km per liter of fuel a 900 kg car that travels 15 km per liter of fuel a 900 kg car that travels 20 km per liter of fuel
Answers
Answered by
GPT-4o mini
To assess the efficiency of the cars listed, we need to consider both weight (mass) and fuel consumption. A common way to measure efficiency in this context is to look at the fuel economy, which is often expressed as kilometers traveled per liter of fuel. However, to account for the weight of the car, we can also look at the distance traveled per unit of fuel per kilogram of car weight.
Let's evaluate the options:
1. **1,200 kg car traveling 15 km/l**
- Efficiency: \( \frac{15 \text{ km}}{1200 \text{ kg}} = 0.0125 \text{ km/kg} \)
2. **1,200 kg car traveling 20 km/l**
- Efficiency: \( \frac{20 \text{ km}}{1200 \text{ kg}} = 0.01667 \text{ km/kg} \)
3. **900 kg car traveling 15 km/l**
- Efficiency: \( \frac{15 \text{ km}}{900 \text{ kg}} = 0.01667 \text{ km/kg} \)
4. **900 kg car traveling 20 km/l**
- Efficiency: \( \frac{20 \text{ km}}{900 \text{ kg}} = 0.02222 \text{ km/kg} \)
Now, comparing the efficiencies calculated:
- The **1,200 kg car** traveling **20 km/l** has an efficiency of **0.01667 km/kg**.
- The **900 kg car** traveling **15 km/l** has an efficiency of **0.01667 km/kg**.
- The **900 kg car** traveling **20 km/l** has the highest efficiency of **0.02222 km/kg**.
Thus, the **900 kg car that travels 20 km per liter of fuel** has the greatest efficiency.
Let's evaluate the options:
1. **1,200 kg car traveling 15 km/l**
- Efficiency: \( \frac{15 \text{ km}}{1200 \text{ kg}} = 0.0125 \text{ km/kg} \)
2. **1,200 kg car traveling 20 km/l**
- Efficiency: \( \frac{20 \text{ km}}{1200 \text{ kg}} = 0.01667 \text{ km/kg} \)
3. **900 kg car traveling 15 km/l**
- Efficiency: \( \frac{15 \text{ km}}{900 \text{ kg}} = 0.01667 \text{ km/kg} \)
4. **900 kg car traveling 20 km/l**
- Efficiency: \( \frac{20 \text{ km}}{900 \text{ kg}} = 0.02222 \text{ km/kg} \)
Now, comparing the efficiencies calculated:
- The **1,200 kg car** traveling **20 km/l** has an efficiency of **0.01667 km/kg**.
- The **900 kg car** traveling **15 km/l** has an efficiency of **0.01667 km/kg**.
- The **900 kg car** traveling **20 km/l** has the highest efficiency of **0.02222 km/kg**.
Thus, the **900 kg car that travels 20 km per liter of fuel** has the greatest efficiency.
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