Asked by Anonymous
Two objects of masses 10.0 kg and 5.00 kg are connected by a light string that passes over a frictionless pulley. The 5.00kg object lies on a smooth incline of angle 40 degrees. Find the accelerations of each object and the tension in the string.
Work:
(10kg)(9.8m/s^2)(sin40)-T=10a
a=4.20m/s^2
T=5a
T=21N
However, the answer is 4.43m/s^2 and 204N.
Work:
(10kg)(9.8m/s^2)(sin40)-T=10a
a=4.20m/s^2
T=5a
T=21N
However, the answer is 4.43m/s^2 and 204N.
Answers
Answered by
bobpursley
No.
The pulling force is 5*anglefunction*g
the angle function is either sin or cosine, I don't know how the 40 deg was measured. If it was measured from the vertical, then it is Cosine.
Then
Pulling force = total mass *a
where total mass is 15kg
The pulling force is 5*anglefunction*g
the angle function is either sin or cosine, I don't know how the 40 deg was measured. If it was measured from the vertical, then it is Cosine.
Then
Pulling force = total mass *a
where total mass is 15kg
Answered by
Anonymous
, or
Then, Equation (1) yields
Then, Equation (1) yields
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