Asked by geiser
A diver jumps off a platform at an initial upward velocity of 20 feet per second into the air above a pool. The height of the diver above the water after jumping can be represented by the function: h(t)=β16t2+20t
β
(
π‘
)
=
β
16
π‘
2
+
20
π‘
Use desmos to graph the function. Identify the x- intercept and interpret its meaning.
(2 points)
Responses
(1.25, 0); The horizontal distance of the length of the jump is 1.25 feet.
(1.25, 0); The horizontal distance of the length of the jump is 1.25 feet.
(0.625, 6.25); The diver will reach a maximum height of 6.25 feet 0.625 seconds after he jumps
(0.625, 6.25); The diver will reach a maximum height of 6.25 feet 0.625 seconds after he jumps
(1.25, 0); The diver will enter the water 1.25 seconds after he jumps
(1.25, 0); The diver will enter the water 1.25 seconds after he jumps
(0, 0); The diver jumps off the platform with an initial height of o feet.
(0, 0); The diver jumps off the platform with an initi
β
(
π‘
)
=
β
16
π‘
2
+
20
π‘
Use desmos to graph the function. Identify the x- intercept and interpret its meaning.
(2 points)
Responses
(1.25, 0); The horizontal distance of the length of the jump is 1.25 feet.
(1.25, 0); The horizontal distance of the length of the jump is 1.25 feet.
(0.625, 6.25); The diver will reach a maximum height of 6.25 feet 0.625 seconds after he jumps
(0.625, 6.25); The diver will reach a maximum height of 6.25 feet 0.625 seconds after he jumps
(1.25, 0); The diver will enter the water 1.25 seconds after he jumps
(1.25, 0); The diver will enter the water 1.25 seconds after he jumps
(0, 0); The diver jumps off the platform with an initial height of o feet.
(0, 0); The diver jumps off the platform with an initi
Answers
Answered by
GPT-4o mini
To analyze the function \( h(t) = -16t^2 + 20t \), we can find the x-intercepts by setting \( h(t) \) equal to zero:
\[
-16t^2 + 20t = 0
\]
Factoring out \( t \):
\[
t(-16t + 20) = 0
\]
This gives us two solutions:
1. \( t = 0 \)
2. \( -16t + 20 = 0 \) β \( 16t = 20 \) β \( t = \frac{20}{16} = 1.25 \)
The x-intercepts are at \( t = 0 \) and \( t = 1.25 \).
### Interpretation of the x-intercepts:
- At \( t = 0 \): This means that the diver jumps off the platform at an initial height of 0 feet.
- At \( t = 1.25 \): This means that the diver will enter the water 1.25 seconds after he jumps.
Thus, the correct interpretation of the x-intercept \( (1.25, 0) \) is **"The diver will enter the water 1.25 seconds after he jumps."**
\[
-16t^2 + 20t = 0
\]
Factoring out \( t \):
\[
t(-16t + 20) = 0
\]
This gives us two solutions:
1. \( t = 0 \)
2. \( -16t + 20 = 0 \) β \( 16t = 20 \) β \( t = \frac{20}{16} = 1.25 \)
The x-intercepts are at \( t = 0 \) and \( t = 1.25 \).
### Interpretation of the x-intercepts:
- At \( t = 0 \): This means that the diver jumps off the platform at an initial height of 0 feet.
- At \( t = 1.25 \): This means that the diver will enter the water 1.25 seconds after he jumps.
Thus, the correct interpretation of the x-intercept \( (1.25, 0) \) is **"The diver will enter the water 1.25 seconds after he jumps."**