The distribution of the data is skewed to the right, as there are more values concentrated at the lower end (0-4 siblings), while the higher values (5 or more siblings) have significantly fewer occurrences; therefore, the median is the most appropriate measure of center.
To calculate the mean:
\[ \text{Mean} = \frac{(0 \times 4) + (1 \times 5) + (2 \times 3) + (3 \times 4) + (4 \times 2) + (5 \times 0) + (6 \times 1) + (7 \times 2) + (8 \times 0) + (9 \times 0) + (10 \times 1)}{(4 + 5 + 3 + 4 + 2 + 0 + 1 + 2 + 0 + 0 + 1)} \]
\[ = \frac{(0) + (5) + (6) + (9) + (8) + (0) + (6) + (14) + (0) + (0) + (10)}{(22)} \]
\[ = \frac{58}{22} \approx 2.64 \]
Calculating the median:
When we list the data based on occurrences:
- 0 (4 times),
- 1 (5 times),
- 2 (3 times),
- 3 (4 times),
- 4 (2 times),
- 6 (1 time),
- 7 (2 times),
- 10 (1 time)
The total is 22 data points, and the median will be the average of the 11th and 12th values, which are both '2' and '3'. So:
\[ \text{Median} = \frac{2 + 3}{2} = 2.5 \]
Thus, the mean is approximately 2.64, the median is 2.5, and the best measure of center for the number of siblings is the median due to the skewed distribution.