Question
In cubic feet, what’s the volume of a toy box with a length of 4 1/5 ft, a width of 2 1/3 ft, and a height of 3 1/2 ft, the answer will be a mixed fraction in cubic feet
Answers
GPT-4o mini
To find the volume of the toy box in cubic feet, we can use the formula for volume:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
First, we need to convert the mixed fractions into improper fractions.
1. **Convert Length (4 1/5 ft) to an improper fraction:**
\[
4 \frac{1}{5} = \frac{4 \times 5 + 1}{5} = \frac{20 + 1}{5} = \frac{21}{5}
\]
2. **Convert Width (2 1/3 ft) to an improper fraction:**
\[
2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3}
\]
3. **Convert Height (3 1/2 ft) to an improper fraction:**
\[
3 \frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2}
\]
Now we can calculate the volume:
\[
\text{Volume} = \left( \frac{21}{5} \right) \times \left( \frac{7}{3} \right) \times \left( \frac{7}{2} \right)
\]
Multiplying the numerators and the denominators:
\[
\text{Numerator} = 21 \times 7 \times 7 = 21 \times 49 = 1029
\]
\[
\text{Denominator} = 5 \times 3 \times 2 = 30
\]
Thus, the volume in improper fraction form is:
\[
\text{Volume} = \frac{1029}{30}
\]
Next, we will convert this improper fraction back into a mixed fraction. To do this, we divide 1029 by 30.
\[
1029 \div 30 = 34 \text{ (whole number)} \quad \text{with a remainder of } 9
\]
This means:
\[
1029 = 30 \times 34 + 9
\]
Therefore, the mixed fraction is:
\[
34 \frac{9}{30}
\]
We can simplify \(\frac{9}{30}\):
\[
\frac{9}{30} = \frac{3}{10}
\]
So the volume of the toy box is:
\[
\boxed{34 \frac{3}{10}} \text{ cubic feet}
\]
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
First, we need to convert the mixed fractions into improper fractions.
1. **Convert Length (4 1/5 ft) to an improper fraction:**
\[
4 \frac{1}{5} = \frac{4 \times 5 + 1}{5} = \frac{20 + 1}{5} = \frac{21}{5}
\]
2. **Convert Width (2 1/3 ft) to an improper fraction:**
\[
2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3}
\]
3. **Convert Height (3 1/2 ft) to an improper fraction:**
\[
3 \frac{1}{2} = \frac{3 \times 2 + 1}{2} = \frac{6 + 1}{2} = \frac{7}{2}
\]
Now we can calculate the volume:
\[
\text{Volume} = \left( \frac{21}{5} \right) \times \left( \frac{7}{3} \right) \times \left( \frac{7}{2} \right)
\]
Multiplying the numerators and the denominators:
\[
\text{Numerator} = 21 \times 7 \times 7 = 21 \times 49 = 1029
\]
\[
\text{Denominator} = 5 \times 3 \times 2 = 30
\]
Thus, the volume in improper fraction form is:
\[
\text{Volume} = \frac{1029}{30}
\]
Next, we will convert this improper fraction back into a mixed fraction. To do this, we divide 1029 by 30.
\[
1029 \div 30 = 34 \text{ (whole number)} \quad \text{with a remainder of } 9
\]
This means:
\[
1029 = 30 \times 34 + 9
\]
Therefore, the mixed fraction is:
\[
34 \frac{9}{30}
\]
We can simplify \(\frac{9}{30}\):
\[
\frac{9}{30} = \frac{3}{10}
\]
So the volume of the toy box is:
\[
\boxed{34 \frac{3}{10}} \text{ cubic feet}
\]