To graph the linear equation \( y = 23x - 1 \), we can follow a few steps:
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Identify the slope and y-intercept:
- The equation is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
- Here, the slope \( m = 23 \) and the y-intercept \( b = -1 \).
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Plot the y-intercept:
- Start by plotting the point (0, -1) on the y-axis.
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Use the slope to find another point:
- Since the slope is \( 23 \), this means that for each increase of 1 in \( x \), \( y \) increases by 23.
- From (0, -1), if we increase \( x \) by 1, \( y \) becomes \( 23(1) - 1 = 22 \). So the point (1, 22) can be plotted.
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Draw the line:
- Once two points (0, -1) and (1, 22) are plotted, draw a line through these points extending in both directions.
However, based on the provided descriptions of the graphs, none of the options seem to fit precisely with the equation \( y = 23x - 1 \). The points described for each option do not reflect the very steep slope of 23 or the correct y-intercept of -1.
If you're looking for the most accurate representation for \( y = 23x - 1 \), you would expect:
- The line will be very steep because of the high slope.
- The points on the line would go significantly higher in the y-direction as x increases due to the steep slope.
Make sure to plot the line correctly on a graph if working with graph paper or graphing software, and confirm the range of your axes can accommodate the steepness of the line.