–7c + 3c – 6 = 14

Question

[?]c – 6 = 14 (–7c and 3c go in the [?])
c = [?]

Answer 1

To simplify the equation \(-7c + 3c - 6 = 14\), we first combine the like terms \(-7c\) and \(3c\):

\[ -7c + 3c = -4c \]

This gives us:

\[ -4c - 6 = 14 \]

Now, we want to isolate \(c\). First, we can add \(6\) to both sides of the equation:

\[ -4c - 6 + 6 = 14 + 6 \]

This simplifies to:

\[ -4c = 20 \]

Next, we divide both sides by \(-4\):

\[ c = \frac{20}{-4} \]

This simplifies to:

\[ c = -5 \]

Thus, the filled parts of your question are as follows:

1. \([-4]\) goes in the \([?]\).
2. The final value of \(c\) is \([-5]\).

So the answers are:

\[ [?] = -4, \quad c = -5 \]