Question

el!
1
week streak

Level 4
0 /4 skills
Course: 6th grade
>
Unit 11
Lesson 2: Dot plots & frequency tables
Math>6th grade>Data and statistics>Dot plots & frequency tables
© 2025 Khan Academy
Terms of usePrivacy PolicyCookie Notice

Estimate center using dot plots
Problem
The following dot plots show the numbers of people per table at a bingo hall on two nights. Each dot represents one of the
\[20\] tables.
"A dot plot. The number line, labeled People per table Tuesday, is numbered 0 to 9.
Point 4 has 1 dot.
Point 5 has 1 dot.
Point 6 has 2 dots.
Point 7 has 6 dots.
Point 8 has 9 dots.
Point 9 has 1 dot."
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[6\]
\[7\]
\[8\]
\[9\]
"A dot plot. The number line, labeled People per table Wednesday, is numbered 0 to 9.
Point 0 has 5 dots.
Point 4 has 3 dots.
Point 5 has 3 dots.
Point 6 has 5 dots.
Point 7 has 2 dots.
Point 8 has 1 dot.
Point 9 has 1 dot."
\[0\]
\[1\]
\[2\]
\[3\]
\[4\]
\[5\]
\[6\]
\[7\]
\[8\]
\[9\]
Compare the typical number of people per table.
In general, there were more people per table on

, with

per table.
Related content

Answer 1

To compare the typical number of people per table on Tuesday and Wednesday based on the dot plots you've provided, we need to estimate the center of the distributions for both days.

### Tuesday's Dot Plot
- **People per table**:
- 4: 1 dot
- 5: 1 dot
- 6: 2 dots
- 7: 6 dots
- 8: 9 dots
- 9: 1 dot

**Calculation of the average (mean):**
1. Multiply each number of people by the number of tables (dots):
- \(4 \times 1 = 4\)
- \(5 \times 1 = 5\)
- \(6 \times 2 = 12\)
- \(7 \times 6 = 42\)
- \(8 \times 9 = 72\)
- \(9 \times 1 = 9\)

2. Sum these products:
\[
4 + 5 + 12 + 42 + 72 + 9 = 144
\]

3. Divide by the total number of tables (20):
\[
\text{Average for Tuesday} = \frac{144}{20} = 7.2
\]

### Wednesday's Dot Plot
- **People per table**:
- 0: 5 dots
- 4: 3 dots
- 5: 3 dots
- 6: 5 dots
- 7: 2 dots
- 8: 1 dot
- 9: 1 dot

**Calculation of the average (mean):**
1. Multiply each number of people by the number of tables (dots):
- \(0 \times 5 = 0\)
- \(4 \times 3 = 12\)
- \(5 \times 3 = 15\)
- \(6 \times 5 = 30\)
- \(7 \times 2 = 14\)
- \(8 \times 1 = 8\)
- \(9 \times 1 = 9\)

2. Sum these products:
\[
0 + 12 + 15 + 30 + 14 + 8 + 9 = 88
\]

3. Divide by the total number of tables (20):
\[
\text{Average for Wednesday} = \frac{88}{20} = 4.4
\]

### Comparison
In general, there were more people per table on **Tuesday**, with an average of **7.2** people per table compared to **4.4** on Wednesday.