Question
Volume of Pyramids Quick Check
4 of 54 of 5 Items
Question
A cell phone telecommunication tower stands in the shape of a rectangular pyramid. The tower stands 80 m tall and rests on a base that is 15 m by 20 m. What is the volume of the tower?(1 point)
Responses
12,000 m3
12,000 m cubed
70 m3
70 m cubed
8,000 m3
8,000 m cubed
24,000 m3
4 of 54 of 5 Items
Question
A cell phone telecommunication tower stands in the shape of a rectangular pyramid. The tower stands 80 m tall and rests on a base that is 15 m by 20 m. What is the volume of the tower?(1 point)
Responses
12,000 m3
12,000 m cubed
70 m3
70 m cubed
8,000 m3
8,000 m cubed
24,000 m3
Answers
GPT-4o mini
The volume \( V \) of a pyramid is calculated using the formula:
\[
V = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]
In this case, the base is a rectangle with dimensions 15 m and 20 m. First, let's calculate the area of the base:
\[
\text{Base Area} = 15 \, \text{m} \times 20 \, \text{m} = 300 \, \text{m}^2
\]
The height of the pyramid is given as 80 m. Now we can substitute the values into the volume formula:
\[
V = \frac{1}{3} \times 300 \, \text{m}^2 \times 80 \, \text{m}
\]
\[
V = \frac{1}{3} \times 24000 \, \text{m}^3
\]
\[
V = 8000 \, \text{m}^3
\]
Therefore, the volume of the tower is **8,000 m³**.
\[
V = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]
In this case, the base is a rectangle with dimensions 15 m and 20 m. First, let's calculate the area of the base:
\[
\text{Base Area} = 15 \, \text{m} \times 20 \, \text{m} = 300 \, \text{m}^2
\]
The height of the pyramid is given as 80 m. Now we can substitute the values into the volume formula:
\[
V = \frac{1}{3} \times 300 \, \text{m}^2 \times 80 \, \text{m}
\]
\[
V = \frac{1}{3} \times 24000 \, \text{m}^3
\]
\[
V = 8000 \, \text{m}^3
\]
Therefore, the volume of the tower is **8,000 m³**.