To find the volume of a rectangular pyramid, we can use the formula:
\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
Given the side length of the base (which is square) is 12 meters, the base area can be calculated as:
\[ \text{Base Area} = \text{side length} \times \text{side length} = 12 , \text{m} \times 12 , \text{m} = 144 , \text{m}^2 \]
The height of the pyramid is given as 10 meters. Now we can substitute these values into the volume formula:
\[ \text{Volume} = \frac{1}{3} \times 144 , \text{m}^2 \times 10 , \text{m} = \frac{1}{3} \times 1440 , \text{m}^3 = 480 , \text{m}^3 \]
Therefore, the volume of the rectangular pyramid is:
480 m³