The volume \( V \) of a rectangular pyramid can be calculated using the formula:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
In this case, the base is a rectangle with a length of 12 m and a width of 12 m. Therefore, the area of the base \( A \) is:
\[ A = \text{Length} \times \text{Width} = 12 , \text{m} \times 12 , \text{m} = 144 , \text{m}^{2} \]
The height of the pyramid is given as 10 m.
Now, we can plug these values into the volume formula:
\[ V = \frac{1}{3} \times 144 , \text{m}^{2} \times 10 , \text{m} \]
\[ V = \frac{1}{3} \times 1440 , \text{m}^{3} \]
\[ V = 480 , \text{m}^{3} \]
Thus, the volume of the rectangular pyramid is 480 m³.