Question
A spinner has 10 equal-sized sections. To win the game, the pointer must land on a yellow section. Complete the statement.
P(yellow)equalsStartFraction favorable outcomes Over total number of possible outcomes EndFraction
equalsStartFraction question mark Over 10 EndFraction
equals?
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Part 1
P(yellow)equalsStartFraction favorable outcomes Over total number of possible outcomes EndFraction
equalsStartFraction 2 Over 10 EndFraction
equals
5
(Type integers or simplified fractions.)
P(yellow)equalsStartFraction favorable outcomes Over total number of possible outcomes EndFraction
equalsStartFraction question mark Over 10 EndFraction
equals?
LOADING... Click the icon to view the spinner.
Question content area bottom
Part 1
P(yellow)equalsStartFraction favorable outcomes Over total number of possible outcomes EndFraction
equalsStartFraction 2 Over 10 EndFraction
equals
5
(Type integers or simplified fractions.)
Answers
GPT-4o mini
To calculate the probability of landing on a yellow section of the spinner, we can use the formula:
\[ P(yellow) = \frac{\text{favorable outcomes}}{\text{total number of possible outcomes}} \]
From the problem, we know:
- Total number of possible outcomes (the total sections on the spinner) = 10
- Favorable outcomes (the number of yellow sections) = 2
Now we can substitute these values into the formula:
\[ P(yellow) = \frac{2}{10} \]
To simplify this fraction:
\[ \frac{2}{10} = \frac{1}{5} \]
So the final statement is:
\[ P(yellow) = \frac{2}{10} = \frac{1}{5} \]
Thus, the probability of spinning and landing on a yellow section is \(\frac{1}{5}\).
\[ P(yellow) = \frac{\text{favorable outcomes}}{\text{total number of possible outcomes}} \]
From the problem, we know:
- Total number of possible outcomes (the total sections on the spinner) = 10
- Favorable outcomes (the number of yellow sections) = 2
Now we can substitute these values into the formula:
\[ P(yellow) = \frac{2}{10} \]
To simplify this fraction:
\[ \frac{2}{10} = \frac{1}{5} \]
So the final statement is:
\[ P(yellow) = \frac{2}{10} = \frac{1}{5} \]
Thus, the probability of spinning and landing on a yellow section is \(\frac{1}{5}\).