To derive the equation of the line in slope-intercept form (\(y = mx + b\)), we first need to determine the slope (m) and the y-intercept (b).
From the points provided:
- Point 1: \((0, -4)\)
- Point 2: \((1, -1)\)
Step 1: Calculate the slope (m)
The formula for the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points: \((x_1, y_1) = (0, -4)\) and \((x_2, y_2) = (1, -1)\),
\[ m = \frac{-1 - (-4)}{1 - 0} = \frac{-1 + 4}{1} = \frac{3}{1} = 3 \]
Step 2: Find the y-intercept (b)
Now, we can use the slope \(m = 3\) and one of the points to find \(b\). Using the point \((0, -4)\):
\[ y = mx + b \] \[ -4 = 3(0) + b \] \[ -4 = b \]
Step 3: Write the equation in slope-intercept form
Now we can substitute \(m\) and \(b\) back into the slope-intercept form:
\[ y = 3x - 4 \]
Thus, the equation of the line in slope-intercept form is:
\[ \boxed{y = 3x - 4} \]
The correct response from the options provided is y = 3x - 4.